Question

A metal of length 15.01m is heated until it's temperature rise by 60c.if it is new length is 15.05cm ,calculate it linear expansivity

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Answer 1

`\alpha = 4.44 * 10^(-5) ^\circ C^(-1)`

Step-by-step explanation:

Given

`L_1 = 15.01m`

`L_2 = 15.05m`

`\triangle T = 60^\circ C`

Required

Determine its linear expansivity

This is calculated as:

`\alpha = (L_2 - L_1)/(\triangle T * L1)`

`\alpha = (15.05m - 15.01m)/(60^\circ C* 15.01m)`

`\alpha = (0.04m)/(60^\circ C * 15.01m)`

`\alpha = (0.04)/(60^\circ C* 15.01)`

`\alpha = (0.04)/(900.6^\circ C)`

`\alpha = 0.00004441483^\circ C^(-1)`

`\alpha = 4.441483 * 10^(-5) ^\circ C^(-1)`

`\alpha = 4.44 * 10^(-5) ^\circ C^(-1)`