Answer:
Explanation:
Distance between (2,1) and (3,3) = √5
parametric equations for circle of radius √5, centered at (2,1):
x = √5cosθ+2
y = √5sinθ+1
At (3,3), θ = arccos(1/√5) ≅ 63.4°
After 45° transformation:
θ' = 63.4° + 45° = 108.4°
x' = √5cos(108.4°)+2 = 1.29
y' = √sin(108.4°)+1 = 3.12
(3,3) transformed to (1.29,3.12)