Question

Suppose a triangle has two sides of length 32 and 35, and that the angle

between these two sides is 120°. Which equation should you solve to find the
length of the third side of the triangle?
A. C2 = 322 + 352 – 2(32)(35)sin120°
B. sin32
sin35
b
120
C. C= 32 + 35 - 2(32)(35)cos120°
D. 2 = 322 + 352 - 2(32)(35)cos120°

Answer 1

D

Explanation:

It is the law of cos

C^2= A^2+B^2-2*A*B*cosL where L is the angle between A and B

so C = 32^2 + 35^2 - 2(32)(35)cos120°