Question

What is 2x-40y=73 and 7x+65y=332?

Answer 1

I hope you understand your answer is this

Answer 2

`\large\mathfrak{{\pmb{\underline{\orange{Given }}{\orange{:}}}}}`

`2x - 40y = 73...(i)`

`7x + 65y = 332...(ii)`

`\large\mathfrak{{\pmb{\underline{\pink{To\:find }}{\pink{:}}}}}`

The values of
`x` and
`y`.

`\large\mathfrak{{\pmb{\underline{\green{Solution }}{\green{:}}}}}`

`x=43.96` and
`y = 0.373`.

`\large\mathfrak{{\pmb{\underline{\purple{Step-by-step\:explanation}}{\purple{:}}}}}`

Let us solve this by substitution method.

From
`eqn.\:(i),\:we\:have`

↬
`2x - 40y = 73`

↬
`2x = 73 + 40y`

↬
`x = (73 + 40y)/(2)...(iii) \\`

Substituting the value of
`x` in
`eqn.\:(ii)` gives us

↬
`7( (73 + 40y)/(2) ) + 65y = 332 \\`

↬
`(511 + 280y)/(2) + (65y * 2)/(1 * 2) = 332 \\`

↬
`(511 + 280y + 130y)/(2) = 332 \\`

↬
`410y + 511 = 332 * 2`

↬
`410y = 664 - 511`

↬
`y = (153)/(410) \\`

↬
`y = 0.373`

Now, plug the value of
`y` in
`eqn.\:(i)`

↬
`2x - 40 * 0.373 = 73 \\`

↬
`2x - 14.92= 73`

↬
`2x = 73 +14.92`

↬
`x = (87.92)/(2) \\`

↬
`x = 43 .96`

Therefore, the values of
`x` and
`y` are
`\boxed{ 43.96 }` and
`\boxed{ 0.373 }` respectively.

`\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}`