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How do you differentiate y = 3x3 - 2x-4

User Cedrick
by
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1 Answer

7 votes

Answer:

y' = 9x^2 + 8x^-5

Explanation:

General Principle

y' = ax^b

y' = a*b * x^(b-1)

Solution

3x^3 = 3*3x^(3-1)

3x^3 = 9x^2

-2x^-4 = -2*-4 x ^(-4 - 1)

-2x^-4 = 8 x ^-5

Answer

y' = 9x^2 + 8x^-5

User Wormsparty
by
8.7k points

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