Question

Your physics TA has a far point of 0.759 m from her eyes and is able to see distant objects in focus when wearing glasses with a refractive power of −1.35 D. Determine the distance between her glasses and eyes.

Answer 1

`d=0.019m`

Step-by-step explanation:

From the question we are told that:

Far point
`x=0.759m`

Refractive power
`P=-1.35 D.`

Generally, the equation for Focal length is mathematically given by

`F=(1)/(P)`

`F=(1)/(-1.35)`

`F=-0.74m`

Therefore

`(1)/(f)=(1)/(u)+(1)/(v)`

Where

`u=o`

`(1)/(-0.74)=(1)/(0)+(1)/(v)`

`v=-0.74m`

Therefore,The between her glasses and eyes

`d=x-v`

`d=0.759-0.74m`

`d=0.019m`