Answer:
i dont now
Explanation:
inde man kona ka balo sorry
quadrant 1 and quadrant IV
(a)
secθ > 0 in quadrants 1 and IV
sinθ > 0 in quadrants 1 and II
Thus θ is in quadrant I
(b)
cosθ > 0 in quadrants I and IV
cotθ < 0 in quadrants II and IV
Thus θ is in quadrant IV
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