Answer:
13.2 miles
Explanation:
To solve this, we will need to first solve for the base of the triangle and then use the information we find to solve for the shortest route.
(5.5 + 3.5)² + b² = 15²
9² + b² = 15²
81 + b² = 225
b² = 144
b = 12
Now that we know that the base is 12 miles, we can use that and the 5.5 miles in between Adamsburg and Chenoa to find the shortest route (hypotenuse).
5.5² + 12² = c²
30.25 + 144 = c²
174.25 = c²
13.2 ≈ c
Therefore, the shortest route from Chenoa to Robertsville is about 13.2 miles.