Question

Dy
If x2 - y2 = 1, then
dx
1
(a) yx-1
(C) xy-1
(b) -xy-
(d) - yx​

Answer 1

xy-1

Step-by-step explanation:

Given expression is :

`x^2-y^2=1` ..(1)

We need to find the value of
`(dy)/(dx)`.

Differentiating equation (1) wrt x.

`(d)/(dx)(x^2-y^2)=1\\\\2x-2y* (dy)/(dx)=0\\\\2y* (dy)/(dx)=2x\\\\y* (dy)/(dx)=x\\\\(dy)/(dx)=(x)/(y)`

or

`(dy)/(dx)=xy^(-1)`

Hence, the correct option is (c) "xy-1".