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Joel had 200 coins,
which were dimes and quarters. The total value is $32.

User Farasath
by
8.2k points

1 Answer

5 votes

Answer:

Joel had 120 dimes and 80 quarters.

Explanation:

Given that Joel had 200 coins, which were dimes and quarters, and the total value was $ 32, to determine how many coins of each type he had, the following calculation must be performed:

0.25 - 0.10 = 0.15

200 x 0.10 = 20

32 - 20 = 12

12 / 0.15 = 80

200 - 80 = 120

(80 x 0.25) + (120 x 0.1) = X

20 + 12 = X

32 = X

Thus, Joel had 120 dimes and 80 quarters.

User Ryan Coolwebs
by
8.1k points
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