Question

Silver nitrate reacts with calcium chloride as

shown.
2 AgNO3 + CaCl2 → 2 AgCl + Ca(NO3)2
How many grams of CaCl2 would be required to completely react with 420 mL of
0.506 M AgNO3 solution?
Answer in units of grams.

Answer 1

11.8g of CaCl₂ would be required

Step-by-step explanation:

To solve this question we need to find the moles of AgNO₃ in the solution. Thus, and using the chemical reaction we can find the moles of CaCl₂ required for a complete reaction and its mass as follows:

Moles AgNO₃:

420mL = 0.420L * (0.506mol / L) = 0.213 moles AgNO₃

Moles CaCl₂:

Based on the chemical reaction, 2 moles of AgNO₃ react per mole of CaCl₂.

The moles of CaCl₂ that will react are:

0.213 moles AgNO₃ * (1mol CaCl₂ / 2 mol AgNO₃) = 0.106 moles CaCl₂

Mass CaCl₂ -Molar mass: 110.98g/mol-

0.106 moles CaCl₂ * (110.98g / mol) =

11.8g of CaCl₂ would be required