Question

A source charge of 5. 0 µC generates an electric field of 3. 93 × 105 at the location of a test charge. How far is the test charge from the source charge?.

Answer 1

r = 0.338 meters

Step-by-step explanation:

Q = Source charge

q = Test charge

5μC= 5*10^-6 C

Start with the electric field equation:

`E = (F)/(q)`

and Coulombs law

`F=(k|Qq|)/(r^2)`

Combining these functions we get:

`E=(k|Q|)/(r^2)`

As you can see the test charge cancels so we do not need the value of it.

Plug in your numbers:

`3.93*10^5=((8.99*10^9)(5*10^-^6))/(r^2)`

solve for r

`r=\sqrt{((8.99*10^9)(5*10^-^6))/((3.93*10^5)) }`

`r= 0.338 meters`