Question

A bike tire at a pressure of 740 mmHg and a

temperature of 290 K has a volume of 2.2 liters.
A child gets on the bike and rides it outside.
What is the new pressure if the temperature
outside is 296 K and his weight causes the tire's
volume to drop to 2.0 liters?

Answer 1

Answer: The new pressure is 831 mm Hg

Step-by-step explanation:

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 740 mm Hg

`P_2` = final pressure of gas = ?

`V_1` = initial volume of gas = 2.2 L

`V_2` = final volume of gas = 2.0 L

`T_1` = initial temperature of gas = 290 K

`T_2` = final temperature of gas = 296 K

Now put all the given values in the above equation, we get:

`(740* 2.2)/(290)=(P_2* 2.0)/(296)`

`P_2=831mmHg`

The new pressure is 831 mm Hg