Question

How many moles are in 2.5L of 1.75 M Na2CO3

Answer 1

4.375 moles Na2CO3

Step-by-step explanation:

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Answer 2

4.375 moles Na2CO3

Step-by-step explanation:

Formula for molarity is;

M = n/V

Where;

M is molarity

n is number of moles

V is volume

Making n the subject we have;

n = VM

We are given;

M = 1.75 M

V = 2.5 L

Thus;

n = 2.5 × 1.75

n = 4.375 moles Na2CO3