Question

2) Calculate the percent composition of each element in Mgso,

3) Calculate the percentage of each element in Ag,o.

Answer 1

2)

`\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%`

3)

`\% Ag=93.1\%\\\\\% O=6.9\%`

Step-by-step explanation:

Hello!

2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:

`\% Mg=(24.305)/(120.36 ) *100\%=20.2\%\\\\\% S=(32.06)/(120.36 ) *100\%=26.6\%\\\\\% O=(64.00)/(120.36 ) *100\%=53.2\%`

3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:

`\% Ag=(215.74)/(231.74) *100\%=93.1\%\\\\\% O=(16.00)/(231.74) *100\%=6.9\%`

Best regards!