439,641 views
32 votes
32 votes
X-2/x+2-3/x-2=2*(x-11)/x^2-4

User Mister Verleg
by
2.2k points

1 Answer

7 votes
7 votes

9514 1404 393

Answer:

x = 4 or x = 5

Explanation:

Maybe you want to solve ...


(x-2)/(x+2)-(3)/(x-2)=2(x-11)/(x^2-4)\\\\((x-2)^2-3(x+2)-2(x-11))/(x^2-4)=0\\\\(x^2 -4x+4-3x-6-2x+22)/(x^2-4)=0=(x^2-9x+20)/(x^2-4)\\\\{x^2-9x+20}=0=(x-5)(x-4)\ \Rightarrow\ x=\{4,5\}

The solutions are x=4 and x=5.

_____

Additional comment

The Order of Operations requires that we interpret your input as ...

x -(2/x) +2 -(3/x) -2 = (2(x -11)/x^2) -4

This is probably not what you want.

In order to get the interpretation we have used above, you need to use parentheses around any numerator or denominator containing arithmetic operations:

(x -2)/(x +2) -3/(x -2) = 2(x -11)/(x^2 -4)

X-2/x+2-3/x-2=2*(x-11)/x^2-4-example-1
User Iurii Budnikov
by
2.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.