Question

Point p is the interior of angle abc. If angle abc=125deg and angle abp=62deg, what is the angle pbc?

Answer 1

Answer: The angle ∠ PBC is 63°.

Explanation:

Given: Point P is in the interior of ∠ABC.

∠ ABC = 125°

∠ABP= 62°

To find : ∠ PBC

Since P is in the interior of ∠ABC.

Then

∠ ABC = ∠ABP + ∠ PBC

⇒ 125°= 62°+ ∠ PBC

⇒ ∠ PBC= 125° - 62°

⇒ ∠ PBC= 63°

Hence, the angle ∠ PBC is 63°.