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The length of a rectangular picture frame is 4 inches shorter than its width. If the perimeter of the picture frame is 44 inches, what is the length, l, and width, w, of the frame? Write and solve an equation to model the problem.

User Nifim
by
4.9k points

2 Answers

10 votes

Final answer:

The width of the frame is 13 inches and the length is 9 inches.

Step-by-step explanation:

Let's say the width of the frame is w inches. According to the problem, the length of the frame is 4 inches shorter than its width, so the length is w - 4 inches.

The perimeter of a rectangle is given by the formula P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Since the perimeter of the frame is 44 inches, we can set up the following equation:

44 = 2(w - 4 + w)

Simplifying the equation, we get:

44 = 2(2w - 4)

Now, we can solve for w:

44 = 4w - 8

52 = 4w

w = 13

Therefore, the width of the frame is 13 inches. The length can be found by substituting the width value into the expression w - 4:

l = 13 - 4 = 9

So, the length of the frame is 9 inches.

User Bwing
by
4.6k points
5 votes

Answer:

11

Step-by-step explanation:

44*4=44

User Nelsi
by
5.2k points