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Calculate the molarity of 29.25 grams of NaCI in 2.0 liters of solution

2 Answers

4 votes

Final answer:

The molarity of the solution is 0.25 M

Step-by-step explanation:

To calculate the molarity of a solution, you need to use the formula:

Molarity = (moles of solute) / (volume of solution in liters)

In this case, you are given the mass of NaCl (29.25 grams) and the volume of the solution (2.0 liters). First, convert the mass of NaCl to moles using its molar mass (58.44 g/mol). Then divide the moles by the volume of the solution in liters to get the molarity.

Using the given values:

Moles of NaCl = (29.25 grams) / (58.44 g/mol) = 0.5 moles

Molarity = (0.5 moles) / (2.0 liters) = 0.25 M

User NID
by
4.1k points
1 vote

Answer:

[NaCl(aq)] = 0.25M

Step-by-step explanation:

Molarity = moles solute / volume of solution in liters

moles NaCl in 29.25 grams = 29.25g/58g·mol⁻¹ = 0.5043 mole

Molarity = 0.5043 mole NaCl / 2 Liters = 0.2555M ≅ 0.25M (2 sig-figs)

User SagiZiv
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