Write a sine function that has a midline of 5, an amplitude of 4 and a period of 7/5

Soob asked Nov 11, 2023

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15 votes

Soob asked Nov 11, 2023

by Soob

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20 votes

Answer:

$y=4sin((10\pi)/(7)x)+5$

Explanation:

Recall formula

$y=asin(bx+c)+d\\\\y=4sin(bx)+5$

Determine b from period

$(2\pi)/(b)=(7)/(5)\\ \\ 10\pi=7b\\\\b=(10\pi)/(7)$

Final Equation

$y=4sin((10\pi)/(7)x)+5$

Smido answered Nov 15, 2023

by Smido

2.8k points

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