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Consider this equation. cos(theta) = (-2√5)/5. If theta is an angle in quadrant II, what is the value of sin(theta)? NO LINKS!!!​

Consider this equation. cos(theta) = (-2√5)/5. If theta is an angle in quadrant II-example-1
User Nasruddin
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5 votes

Answer:

Explanation:

Consider this equation. cos(theta) = (-2√5)/5. If theta is an angle in quadrant II-example-1
User Moonboy
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  • In second quadrant sin and cosec are positive


\\ \tt\hookrightarrow sin^2\theta=1-cos^2\theta


\\ \tt\hookrightarrow sin^2\theta=1-((-2√(5))/(5))^2


\\ \tt\hookrightarrow sin^2\theta=1-(20)/(25)


\\ \tt\hookrightarrow sin^2\theta=(5)/(25)


\\ \tt\hookrightarrow sin\theta=(√(5))/(5)


\\ \tt\hookrightarrow sin\theta=(1)/(√(5))

User Piotr Wasilewicz
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