Answer:
x = -6, 10
Explanation:
Hi there!
![f(x)=x^2-4x-60](https://img.qammunity.org/2023/formulas/mathematics/high-school/7yl68os276p3wdn11nwx7wiq65ok3z55q1.png)
Let f(x) = 0:
![0=x^2-4x-60](https://img.qammunity.org/2023/formulas/mathematics/high-school/r64lkaiz9bu5m9vkk2p4mjp2vilw1shy9l.png)
Factor the equation:
![0=x^2-10x+6x-60\\0=x(x-10)+6(x-10)\\0=(x+6)(x-10)](https://img.qammunity.org/2023/formulas/mathematics/high-school/w7dogiuac6y7umowwo1ay8mzv7btmkb910.png)
The zero-product property tells us that when two terms are multiplied and they equal zero, one of the terms must be zero.
Therefore, either (x+6) or (x110) is equal to 0:
x+6 = 0 ⇒ x = -6
x-10 = 0 ⇒ x = 10
Therefore, the zeros of f(x) are -6 and 10.
I hope this helps!