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20 votes
20 votes
The equation y=2(x-1)^2-5y=2(x−1)

2
−5y, equals, 2, left parenthesis, x, minus, 1, right parenthesis, squared, minus, 5 is graphed in the xyxyx, y-plane. Which of the following statements about the graph is true?

User Pera
by
3.0k points

2 Answers

15 votes
15 votes

Answer: It is symmetrical about x=1

Explanation:

User Steoates
by
3.4k points
18 votes
18 votes

Answer:

(b) It is symmetrical about
x = 1

Explanation:

Given


y = 2(x - 1)^2 - 5

See attachment for options

Required

True statement about the graph

First, we check the line of symmetric


y = 2(x - 1)^2 - 5

Expand


y = 2(x^2 - 2x + 1) - 5

Open bracket


y = 2x^2 - 4x + 2 - 5


y = 2x^2 - 4x -3

A quadratic equation
y = ax^2 + bx + c has the following line of symmetry


x = -(b)/(2a)

By comparison, the equation becomes:


x = -(-4)/(2*2)


x = (4)/(4)


x = 1

Hence, the line of symmetry is at:
x = 1

(b) is true.

The equation y=2(x-1)^2-5y=2(x−1) 2 −5y, equals, 2, left parenthesis, x, minus, 1, right-example-1
User Oralia
by
3.2k points
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