Question

Jol 28, 3:44:44 AM

Solve the equation for all values of x.
(x2 – 16)(x2 + 49) = 0
Answer:
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Answer 1

x = 4, -4, 7i, -7i

Explanation:

(x^2 – 16)(x^2 + 49) = 0

x^2 – 16 = 0 or x^2 + 49 = 0

x^2 = 16 or x^2 = -49

x = ± 4 or x^2 = ±7√-1 =±7i