Final answer:
To determine the total number of atoms for each element in the given chemical equation 5CaCl2 + 3Ca(ClO4)2 + 4Ca(OH)2, we need to examine the subscripts and coefficients. For calcium (Ca), there are 19 atoms. For chlorine (Cl), there are 18 atoms. And for oxygen (O), there are 18 atoms.
Step-by-step explanation:
In the given chemical equation, 5CaCl2 + 3Ca(ClO4)2 + 4Ca(OH)2, we have to find the total number of atoms for each element. To determine this, we need to examine the subscripts and coefficients in the equation.
For calcium (Ca), we have 5 atoms from CaCl2, 6 atoms from Ca(ClO4)2, and 8 atoms from Ca(OH)2, for a total of 19 calcium atoms.
For chlorine (Cl), we have 10 atoms from CaCl2, and for oxygen (O), we have 2 atoms from Ca(ClO4)2 and 16 atoms from Ca(OH)2, resulting in a total of 18 chlorine atoms and 18 oxygen atoms.