Question

Answer problem below

Answer 1

Solution given:

A(7,9)

B(11,11)

C(6,16)

Slope of AB=
`(11-9)/(11-7)=(2)/(4)=½`

since altitude is perpendicular to it .

so its slope becomes negative reciprocal to the slope of base

so

slope of altitude(m) =-2

now

equation of a line passing through C(6,16) perpendicular to its base is:

By using formula

`y-y_(1)=m(x-x_(1))`

y-16=-2(x-6)

solve it

y-16=-2x+12

y+2x=12+16

in the form of Ax +By=C is:

2x+y=28

:.

A=2

B=1

C=28

Answer 2

• A = 2, B = 1, C = 28

Explanation:

Find the slope of the line AB.

The slope:

• m = (11 - 9)/(11 - 7) = 2/4 = 1/2

Since the altitude is perpendicular to AB, it has a slope of -2.

The line with the slope of -2 and passes through point C(6, 16).

Use point-slope equation to find the line:

• y - 16 = -2(x - 6)
• y - 16 = -2x + 12
• y + 2x = 16 + 12
• 2x + y = 28

A = 2, B = 1, C = 28