Question

The mass in a pendulum clock completes one full back-and-forth oscillation in 1.25s.

What is the length of the rod (assuming its mass is negligible)?

Answer 1

.38m

Step-by-step explanation:

1.25 = 2π√l/g

removing square roots

1.5625 = 4*π^2*l/9.8

length = .38m