Answer:
d. 46.5 g
Step-by-step explanation:
First, you need to start with a properly balanced equation:
N₂H₄(l) + 3O₂(g) -> 2NO₂(g) + 2H₂O(l)
Then, find the moles of water produced:
2H = 2.01568 amu
O = 15.999 amu
________________
18.01468 amu
52.4 g ÷ 18.01468 amu = 2.9087 moles
The mole ratio in our balanced formula between N₂H₄ : H₂O is 1 : 2, so divide moles of H₂O by 2 to get moles of N₂H₄
2.9087 moles ÷ 2 = 1.45435 moles of N₂H₄
Then, calculate the atomic mass of N₂H₄:
2N = 28.0134 amu
4H = 4.03136 amu
________________
32.04476 amu
Finally, calculate the mass in grams of N₂H₄:
1.45435 moles • 32.04476 amu = 46.604 g