Question

What is an

equation of the line that passes through the points (-6, 3) and (-5,2)?
Put your answer in fully reduced form.

Answer 1

Explanation:

y=mx+b

m=(y2-y1)/(x2-x1), (-6,3), (-5,2)

m=(3-2)/(-6+5)=-1

y=-x+b, using point (-6,3) we can solve for b

3=-(-6)+b

3=6+b

b=-3

y=-x-3

Answer 2

your answer is y = -x - 3

Explanation:

Slope is -1

Y intercept is -3

y = mx + b

substitute