44,949 views
40 votes
40 votes
A line passes through (-6,-5) and has the slope of 2/3

HELPPPP PLEASE!!

User Tahir Hassan
by
2.5k points

2 Answers

15 votes
15 votes

Answer:


y = (2)/(3)x - 1

Explanation:


y = mx + c \\ \\ m = slope \\ c = y \: \: intercrept


m = (2)/(3)


y = mx + c \\ - 5 = (2)/(3) * - 6 + c \\ - 5 = ( - 12)/(3) + c \\ - 5 = - 4 + c \\ - 5 + 4 = c \\ - 1 = c

So, the equation of the line is,


y = mx + c \\ y = (2)/(3)x - 1

User Neha Kumari
by
2.7k points
12 votes
12 votes

Answer:

y = 2/3x-1

Explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 2/3x +b

Using the point (-6,-5)

-5 = 2/3(-6)+b

-5 = -4 +b

Add 4 to each side

-5+4 = b

-1 =b

y = 2/3x-1

User Guillaume Lhz
by
3.3k points