Question

A juice machine is set to dispense 16 ounces of juice. The amount of juice

dispensed is normally distributed, with a mean of 16.15 ounces and a
standard deviation of 0.25 ounces. In which range will the amount of juice
dispensed be found 68% of the time?​

Answer 1

A

Explanation:

Answer 2

Answer: A): 15.90 ounces to 16.4 ounces.

Explanation:

Considering the standard deviation is 0.25 ounces. The mean of the juice is 16.15 ounces. Additionally, 68% is one standard deviation away from the mean.

With that being said, you would do the following calculations:

`16.15-0.25=15.90\\\\16.15+0.25=16.40`

This question relates to The Empirical Rule and understanding how it works. A brief summary is that within one standard deviation of the mean, that is where 68% of the data lies. Two standards deviations is 95%. And three standard deviations is 99.5%.

The formula:
`u(+)/(-) o`

the mean PLUS OR MINUS the standard deviation.