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What is
h(x) = 1/(x-5)3

User Cleven
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1 Answer

7 votes

Answer:

lim_( 3\/(-5 + x) = 0

Explanation:

h(x) = 1\/(x - 5)×3

{x element R : x!=5}

{h element R : h!=0}

d\/dx(3\/(x - 5)) = -3\/(x - 5)^2

integral 3\/(x - 5) dx = 3 log(x - 5) +

User Kaldrr
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