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P(x) = x^4 – 2x^3 – 3x^2 + 4 What is the remainder when P(x) is divided by (x – 3)?​
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P(x) = x^4 – 2x^3 – 3x^2 + 4

What is the remainder when P(x) is divided by (x – 3)?​

User Saddan
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2 Answers

15 votes
15 votes

Answer:

4

Explanation:

:)

User Stech
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25 votes
25 votes
Here is the answer using synthetic division method !
P(x) = x^4 – 2x^3 – 3x^2 + 4 What is the remainder when P(x) is divided by (x – 3)?​-example-1
User Bronze Man
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