Question

Observe the given figure and find the the gravitational force between m1 and m2.​

Answer 1

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Step-by-step explanation:

The details of the given masses having gravitational attractive force between them are;

m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m

The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

`F =G \cdot (m_(1) \cdot m_(2))/(r^(2))`

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

`F = 6.67430 * 10^(-11) \ N \cdot m^2/kg * (20 \ kg* 50 \ kg)/((0.1 \ m+ 0.15 \ m)^(2)) \approx 1.06789 * 10^(-6) \ N`

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N