Question

A force of 200 N, acting at 60° to the horizontal, accelerates a block of mass 50 kg along a horizontal plane. Calculate the component of the 200N force that accelerates the block horizontally​

Answer 1

Step-by-step explanation:

a) Fx = F cos (θ)

= (200) cos(60)

= 100 N

b) FR = ma

Fx + Ff = ma

100 + Ff = (50)(1,5)

Ff = 75 - 100

= -25 N

c) Fy = F sin θ

= (200) sin(60)

= 173,2 N