1 mole of KCl → 22.4l
1 mole of KCl → 74.55g
we have
0.14 mole of KCl → 74.55*0.14=10.347g
74.55g of KCl → 22.4l
10.347 g of KCl → 22.4/74.55*10.347=3.11litre
volume of each solution contains 0.14 mol of KCl contain 3.11litre.
Answer:
Solution given:
1 mole of KCl22.4l
1 mole of KCl74.55g
0.14 mole of KCl74.55*0.14=10.347g
74.55g of KCl22.4l
10.347 g of KCl22.4/74.55*10.347=3.11litre
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