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42 votes
Find the first five terms of the following sequence, starting with n=1. tn=(−1)n+1(n2−9) Give your answer as a list, separated by commas. For example, if tn=n, you would give your answer as 1,2,3,4,5.

User Oxalorg
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1 Answer

11 votes
11 votes

Answer:

-8, 5 , 0 , -7 , 16

Explanation:

Given


t_n = (-1)^(n+1)(n^2 - 9)

Required

The first five terms

When
n = 1


t_1 = (-1)^(1+1)(1^2 - 9)


t_1 = (-1)^(2)(1 - 9)


t_1 = -8

When
n =2


t_2 = (-1)^(2+1)(2^2 - 9)


t_2 = (-1)^3 * (4 - 9)


t_2 = 5


t_3 = (-1)^(3+1)(3^2 - 9)


t_3 = (-1)^(4)(9 - 9)


t_3 = 0


t_4 = (-1)^(4+1)(4^2 - 9)


t_4 = (-1)^5(16 - 9)


t_4 = -7


t_5 = (-1)^(5+1)(5^2 - 9)


t_5 = (-1)^(6)(25 - 9)


t_5 = 16

So, the first five terms are: -8, 5 , 0 , -7 , 16

User Nikhil VJ
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