Question

two angles of a triangle measure 59 degrees and 63 degrees. if the longest side measures 28 cm find the length of the shortest side

Answer 1

26, 6487

Explanation:

1) FInd the third angle 180-59-63= 58 degrees.

2) The longest side lies in front of the biggest angle (63degrees) while the shortest side stretches in front of the smallest angle (58degrees). Suppose the side that is searched is equal to x

2) Use the law of sin

28/ sin63degrees= x/ sin 58degrees

28/ 0,891= x/0/848

x= 26. 6487 cm (approximately)