Question

PLEASE HELP What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic

weight of Ca is 40.1 and the atomic weight of Br is 79.9.

A) 452.3 g

B) 53.04 g

C) 44.2 g

D) 88.4 g

Answer 1

Answer: Thus there are 88.4 g of calcium bromide.

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

Molar mass of = 40.1 (1)+ 2(79.9) = 199.9

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}`

`0.442=(x)/(199.9)`

`x=88.4g`

Thus there are 88.4 g of calcium bromide.