409,557 views
39 votes
39 votes

- x ^(2) + 2x - 6 = 0

how to do,I don't know the step

answer is

x = 1 - √(5) i \: \: \: \: \: or \: \: 1 + √(5) i


User Fatfatson
by
2.8k points

1 Answer

7 votes
7 votes

Answer:

there are several methods to "solve a quadratic"

you can look them all up...

Graphing, factoring, completing the square, taking roots, quadratic formula are the common methods....

given the way you are asking the question I think that you are supposed to use the quadratic formula ..

please look at the image of the formula and

realize that you problem has

a=-1

b=2

c=6

just plug in those numbers into the formula and you will get the results in the "answer"

NOTE
√(-x) is written as ix (
√(-25) = 5i )

Explanation:

x= -2+√ (2)²- (4)(-1)(-6)

(2)(-1)

and

x= -2-√ (2)²- (4)(-1)(-6)

(2)(-1)

- x ^(2) + 2x - 6 = 0 how to do,I don't know the step answer is x = 1 - √(5) i \: \: \: \: \: or-example-1
User Melon
by
2.8k points
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