Answer:
1.733 x 10⁻⁴ mole CO₂(g)
Step-by-step explanation:
Assuming the rxn given is at STP conditions ...
C₃H₈ + 5O₂ => 3CO₂ + 4H₂O
Given: Excess = 0.647ml ?(moles) -----
= 0.000647Liters
= 6.47 X 10⁻⁴L/22.4L·mol⁻¹
= 1.733 x 10⁻⁵ mol O₂
moles CO₂ = 3/5(2.89 x 10⁻⁴)mole CO₂ = 1.733 x 10⁻⁵ mole CO₂