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33 votes
33 votes
Mike and Ken shared some stamps. \frac{1}{5} 5 1 ​ of Ken's stamps were \frac{1}{3} 3 1 ​ of Mike's stamps. If Mike gave Ken 24 stamps, Ken would have thrice as many stamps as Mike. Find the number of stamps each of them had in the beginning.

User Michael Grogan
by
2.2k points

1 Answer

12 votes
12 votes

Answer:

Mike had 72 stamps

Ken had 120 stamps

Explanation:

Given


M \to Mike


K \to Ken


(1)/(5) * K = (1)/(3) * M


K + 24 = 3 * ( M - 24)

Required

Find K and M

Make K the subject in:
K + 24 = 3 * ( M - 24)


K = 3 * ( M - 24) - 24

Substitute
K = 3 * ( M - 24) - 24 in
(1)/(5) * K = (1)/(3) * M


(1)/(5) * [3 * ( M - 24) - 24] = (1)/(3) * M

Open brackets


(1)/(5) * [3M - 72 - 24] = (1)/(3) * M


(1)/(5) * [3M -96] = (1)/(3) * M

Multiply both sides by 15


3* [3M -96] = 5 * M


9M -288 = 5M

Collect like terms


9M -5M= 288


4M= 288

Divide both sides by 4


M= 72

Substitute
M= 72 in
K = 3 * ( M - 24) - 24


K = 3 * (72 - 24) - 24


K = 3 * 48 - 24


K = 120

User Robert Fleming
by
2.6k points
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