Question

Heating Curve Question

How much energy is required to raise the temperature of 88 grams of water at 48°C to steam at 138°

Answer 1

Q = 33105.6 J

Step-by-step explanation:

Given that,

Mass of water, m = 88 grams

The temperature raised from 48°C to steam at 138°.

We need to find the energy required to raise the temperature. The formula for the energy required is given by :

`Q=mc\Delta T`

Where

c is specific heat of water, c = 4.18J/g °C

So,

`Q=88* 4.18* (138-48)\\\\Q=33105.6\ J`

So, the required energy is 33105.6 J.