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\sqrt{a^(2)+ab+b^(2)} +\sqrt{ a^(2)+ac+c^(2) } \geq \sqrt{ b^(2)+bc+c^(2)

User Benoit Patra
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1 Answer

25 votes
25 votes

Answer:

Solution given:


\sqrt{a^(2)+ab+b^(2)} +\sqrt{a^(2)+ac+c^(2)}+ \sqrt{ b^(2)+bc+c^(2)}


√((a+b)²) +√( (a+c)² )+√((b+c)²)

a+b+a+c+b+c

2a+2b+2c

2(a+b+c)

User Dhaker
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