Question

Part A

Consider the following balanced reaction: N2(g) + 3 H2(9) - 2 NH3(9) How many moles of NH3 could be produced from 0.500 mol of H2?

Answer 1

0.33 mole of NH₃

Step-by-step explanation:

The balanced equation for the reaction is given below:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles of NH₃

Finally, we shall determine the number of mole of NH₃ that will be produced by the reaction of 0.5 moles of H₂. This can be obtained as follow:

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles of NH₃

Therefore, 0.5 moles of H₂ will react to produce = (0.5 × 2)/3 = 0.33 mole of NH₃.

Thus, 0.33 mole of NH₃ was obtained from the reaction