Answer:
The volume of NO is 22.4L at STP
Step-by-step explanation:
Based on the reaction:
2NH3 + 5/2O2 → 2NO + 3H2O
2 moles of NH3 react with 5/2 moles of O2 to produce 2 moles of NO.
To solve this question, we need to find the moles of each reactant in order to find the limiting reactant as follows:
Moles NH3 -Molar mass: -17.01g/mol-
Using PV = nRT
PV/RT = n
Where P is pressure = 1atm at STP
V is volume = 22.4L
R is gas constant = 0.082atmL/molK
T is absolute temperature = 273.15K
1atm*22.4L/0.082atmL/molK*273.15K = n
n = 1.00 moles of NH3
For a complete reaction of 1.00 moles of NH3 are needed:
1.00 moles NH3 * (5/2moles O2 / 2moles NH3) = 1.25 moles of O2
As there are 1.406 moles of O2, the limiting reactant is NH3
The moles of NO produced are the same than moles of NH3 because 2 moles of NH3 produce 2 moles of NO. The moles of NO are 1.00 moles
And as 1.00moles of gas are 22.4L at STP:
The volume of NO is 22.4L at STP