Final answer:
The net force exerted on a 3000 kg plane with an acceleration of 12 m/s² on takeoff is calculated using Newton's second law of motion, yielding a force of 36000 N.
Step-by-step explanation:
To determine the net force exerted on a plane of mass 3000 kg with an acceleration of 12 m/s2 on takeoff, we can use Newton's second law of motion, which states that the net force (Fnet) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). The formula is expressed as Fnet = m * a.
Plugging in the given values:
Mass (m) = 3000 kg
Acceleration (a) = 12 m/s2
The calculation for the net force is:
Fnet = 3000 kg * 12 m/s2 = 36000 N (newtons).
Therefore, the net force exerted on the plane during takeoff is 36000 N.