Question

What are the zeros of f(x)=x^3+2x^2-7x+4? Which statement is true regarding the behavior of the graph of f at each zero

Answer 1

Explanation:

f(x)=x³+2x²-7x+4

at x=1

f(1)=1³+2(1)²-7(1)+4=1+2-7+4=0

so x=1 is one zero.

1) 1 2 -7 4

| 1 3 -4

___________

1 3 -4 |0

x²+3x-4=0

x²+4x-x-4=0

x(x+4)-1(x+4)=0

(x+4)(x-1)=0

x=-4,1

zeros are -4,1,1

coefficient of leading term is +

so it starts from bottom on the left at ends up on the right.

There is a cusp at x=1

or it decreases on left of 1 and and increases on the right.

at x=-4 ,it increases.

Answer 2

Answer: (-4,0) , (1,0)

Explanation:

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