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Tìm X
3x2-3x×(x-2)-12=0

Tìm X 3x2-3x×(x-2)-12=0-example-1
User Shoaib Anwar
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1 Answer

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17 votes

Answer:


3x^2-3x\left(x-2\right)-12=0


3x^2-3x\left(x-2\right)-12+12=0+12 \longleftarrow (\mathrm{Add\:}12\mathrm{\:to\:both\:sides})


3x^2-3x\left(x-2\right)=12


-3x\left(x-2\right)=-3xx-\left(-3x\right)\cdot \:2


=-3xx+3\cdot \:2x


-3xx+3x^(2)


=3x^(1+1)


=3x^2


3\cdot \:2x=6x


=-3x^2+6x


3x^2-3x^2+6x=12\Longleftarrow Add\:similar\:elements


6x=12


(6x)/(6)=(12)/(6) \Longleftarrow Divide


x=2

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User Alejandro Montilla
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