Question

If CD = 7√3, find AE

I give you 25, PLSS HELPPP

Answer 1

AE = 22.86

Explanation:

In triangle CDE

cos 30° = CD/CE

`(\sqrt 3)/(2) = \frac {7\sqrt 3}{CE}`

`CE= {7\sqrt 3}* (2)/(\sqrt 3)`

`CE= 14`

In triangle BCE

sin 45° = CE/BE

`(1)/(\sqrt 2)= (14)/(BE)`

`BE= 14\sqrt 2`

In triangle ABE

sin 60° = BE/AE

`(\sqrt 3)/(2)= (14\sqrt 2)/(AE)`

`AE= 14\sqrt 2*(2)/(\sqrt 3)`

`AE= (28\sqrt 2)/(\sqrt 3)`

`AE= (28\sqrt 6)/( 3)`

`AE= (68.5857128)/( 3)`

AE = 22.8619043

AE = 22.86